Let the number of missing pages be n and the first missing page p+1.
Then the pages p+1 up to and including p+n are missing, and n times the average of the numbers of the missing pages must be equal to 9808:
n×( ((p+1)+(p+n))/2 ) = 9808
In other words:
n×(2×p+n+1)/2 = 2×2×2×2×613
n×(2×p+n+1) = 2×2×2×2×2×613
One of the two terms n and 2×p+n+1 must be even, and the other one must be odd.
Moreover, the term n must be smaller than the term 2×p+n+1.
It follows that there are only two solutions:
- n=1 and 2×p+n+1=2×2×2×2×2×613, so n=1 and p=9808, so only page 9808 is missing.
- n=2×2×2×2×2 and 2×p+n+1=613, so n=32 and p=290, so the pages 291 up to and including 322 are missing.
Because it is asked which pages (plural) are missing, the solution is: the pages 291 up to and including 322 are missing.
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