Solution to:
Long Division
Replace the dots by letters as follows:
a b 9 / 6 c 8 d e f \ g 5 3
h i j 2

k 9 l m
n p 4 q

r s 4 t
u v w x

0
Because the long division ends without remainder, we know that:
We conclude:
a b 9 / 6 c 8 d e f \ g 5 3
h i j 2

k 9 l e
n p 4 q

r s 4 f
r s 4 f

0
In addition, the following holds:
 ab9 × 3 (of g53) always ends on 7, so f = 7
 ab9 × 3 = rs47, so 3 × b + 2 (of 3 × 9 = 27) = 4, so b = 4
 np4q = 5 × a49 and always ends on 5, so q = 5
This results in:
 e = 9
 g × a49 = hij2, so g = 8
 608097 (smallest possible numerator) divided by 853 gives 712, so a >= 7.
The largest possible numerator (698997) divided by 853 gives 819. So, the only possibility for a is 7.
Now, the other digits can automatically be derived, since both numerator and denominator are known.
The complete long division looks like:
7 4 9 / 6 3 8 8 9 7 \ 8 5 3
5 9 9 2

3 9 6 9
3 7 4 5

2 2 4 7
2 2 4 7

0
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